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PostgreSql查看列信息

Laughing博主
2023-07-14
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07/14
本文最后更新于2023年07月14日,已超过289天没有更新。如果文章内容或图片资源失效,请留言反馈,我会及时处理,谢谢!
select ordinal_position                                                      as Colorder,
       column_name                                                           as ColumnName,
       data_type                                                             as TypeName,
       coalesce(character_maximum_length, numeric_precision, -1)             as Length,
       numeric_scale                                                         as Scale,
       case is_nullable when 'NO' then 0 else 1 end                          as CanNull,
       column_default                                                        as DefaultVal,
       case when position('nextval' in column_default) > 0 then 1 else 0 end as IsIdentity,
       case when b.pk_name is null then 0 else 1 end                         as IsPK,
       c.DeText
from information_schema.columns
         left join (select pg_attr.attname as colname, pg_constraint.conname as pk_name
                    from pg_constraint
                             inner join pg_class on pg_constraint.conrelid = pg_class.oid
                             inner join pg_attribute pg_attr
                                        on pg_attr.attrelid = pg_class.oid and pg_attr.attnum = pg_constraint.conkey[1]
                             inner join pg_type on pg_type.oid = pg_attr.atttypid
                    where pg_class.relname = '表名'
                      and pg_constraint.contype = 'p') b on b.colname = information_schema.columns.column_name
         left join (select attname, description as DeText
                    from pg_class
                             left join pg_attribute pg_attr on pg_attr.attrelid = pg_class.oid
                             left join pg_description pg_desc
                                       on pg_desc.objoid = pg_attr.attrelid and pg_desc.objsubid = pg_attr.attnum
                    where pg_attr.attnum > 0
                      and pg_attr.attrelid = pg_class.oid
                      and pg_class.relname = '表名') c on c.attname = information_schema.columns.column_name
where table_schema = '架构'
  and table_name = '表名'
order by ordinal_position asc
PostgreSQL
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